3h^2-137=0

Solution for 3h^2-137=0 equation:

3h^2-137=0

a = 3; b = 0; c = -137;
Δ = b2-4ac
Δ = 02-4·3·(-137)
Δ = 1644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1644}=\sqrt{4*411}=\sqrt{4}*\sqrt{411}=2\sqrt{411}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{411}}{2*3}=\frac{0-2\sqrt{411}}{6}
=-\frac{2\sqrt{411}}{6}
=-\frac{\sqrt{411}}{3}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{411}}{2*3}=\frac{0+2\sqrt{411}}{6}
=\frac{2\sqrt{411}}{6}
=\frac{\sqrt{411}}{3}
$